As function arguments, passing multidimensional arrays in C. In C, passing multidimensional arrays are no longer used and can be used as function arguments (again in a code library) in C. The examples below illustrate this.

typedef struct {
  int myint;
  char* mystring;
} data;

data** array;

//initialize
int x,y,w,h;
w = 10; //width of array
h = 20; //height of array

//malloc the "y" dimension
array = malloc(sizeof(data*) * h);

//iterate over "y" dimension
for(y=0;y<h;y++){
  //malloc the "x" dimension
  array[y] = malloc(sizeof(data) * w);

  //iterate over the "x" dimension
  for(x=0;x<w;x++){
    //malloc the string in the data structure
    array[y][x].mystring = malloc(50); //50 chars

    //initialize
    array[y][x].myint = 6;
    strcpy(array[y][x].mystring, "w00t");
  }
}

int whatsMyInt(data** arrayPtr, int x, int y){
  return arrayPtr[y][x].myint;
}

printf("My int is %d.
", whatsMyInt(array, 2, 4));

My int is 6.

Tags: c function multidimensional-array

Source: By David as answer to the question

This code snippet was collected from stackoverflow, and is licensed under CC BY-SA 4.0

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As function arguments, passing multidimensional arrays in C. In C, passing multidimensional arrays are no longer used and can be used as function arguments (again in a code library) in C. The examples below illustrate this.

Related code-snippets: